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solve-the-d-e-y-x-y-3-0-




Question Number 30411 by abdo imad last updated on 22/Feb/18
solve the d.e. y+x (y^′ )^3 =0
$${solve}\:{the}\:{d}.{e}.\:{y}+{x}\:\left({y}^{'} \right)^{\mathrm{3}} =\mathrm{0} \\ $$

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