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Question Number 190259 by jlewis last updated on 30/Mar/23
solve the differential   equation.  (d^2 /dt^2 ) x + ω^2 x(t) =0  ;x(0)=0;x^2 (0)=υ_o
solvethedifferentialequation.d2dt2x+ω2x(t)=0;x(0)=0;x2(0)=υo
Commented by mr W last updated on 30/Mar/23
x(t)=(v_0 /ω) sin ωt
x(t)=v0ωsinωt
Commented by mehdee42 last updated on 30/Mar/23
x^2 (0)=0≠v_0
x2(0)=0v0
Commented by mr W last updated on 31/Mar/23
x(0)=0 and x^2 (0)=v_0  is non−sense.  it is meant x′(0)=v_0 , see question  below.
x(0)=0andx2(0)=v0isnonsense.itismeantx(0)=v0,seequestionbelow.
Commented by mehdee42 last updated on 31/Mar/23
exactly.you are right.it was strang for mr too.  the question is typed incorrectly.thank you very much
exactly.youareright.itwasstrangformrtoo.thequestionistypedincorrectly.thankyouverymuch

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