Question Number 99831 by mathmax by abdo last updated on 23/Jun/20
$$\mathrm{solve}\:\mathrm{the}\:\mathrm{ds}\:\:\:\begin{cases}{\mathrm{x}^{'} \:+\mathrm{2y}^{'} \:=\mathrm{sint}}\\{\mathrm{3x}^{'} +\mathrm{y}^{'} \:=\mathrm{te}^{\mathrm{t}} }\end{cases} \\ $$