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Question Number 63383 by minh2001 last updated on 03/Jul/19
solve this equation in all   part of complex number:  (√((x^9 −3x^2 +1)(x−6)+4))=(x^9 −3x^2 +1)(x−6)−16
solvethisequationinallpartofcomplexnumber:(x93x2+1)(x6)+4=(x93x2+1)(x6)16
Commented by MJS last updated on 04/Jul/19
waiting to see your solution
waitingtoseeyoursolution
Answered by MJS last updated on 03/Jul/19
(√(t+4))=t−16  t+4=(t−16)^2   t^2 −33t+252=0  ⇒ t=12∨t=21  but t=12 is no solution of (√(t+4))=t−16  ⇒ t=21  (x^9 −3x^2 +1)(x−6)=21  (x+1)(x^9 −7x^8 +7x^7 −7x^6 +7x^5 −7x^4 +7x^3 −10x^2 +28x−27)=0  x_1 =−1  we cannot exactly solve the rest  x_2 ≈6.00000208  the other 8 roots are complex (4 pairs of conjugated complex roots)  if it′s  (√((x^3 −3x^2 +1)(x−6)+4))=(x^3 −3x^2 +1)(x−6)−16  we can:  (x^3 −3x^2 +1)(x−6)=21  (x+1)(x^3 −10x^2 +28x−27)=0  x_1 =−1  x_2 =((10)/3)+((((209)/(54))−((√(337))/6)))^(1/3) +((((209)/(54))+((√(337))/6)))^(1/3)   x_3 =((10)/3)+(−(1/2)−((√3)/2)i)((((209)/(54))−((√(337))/6)))^(1/3) +(−(1/2)+((√3)/2)i)((((209)/(54))+((√(337))/6)))^(1/3)   x_4 =((10)/3)+(−(1/2)+((√3)/2)i)((((209)/(54))−((√(337))/6)))^(1/3) +(−(1/2)−((√3)/2)i)((((209)/(54))+((√(337))/6)))^(1/3)
t+4=t16t+4=(t16)2t233t+252=0t=12t=21butt=12isnosolutionoft+4=t16t=21(x93x2+1)(x6)=21(x+1)(x97x8+7x77x6+7x57x4+7x310x2+28x27)=0x1=1wecannotexactlysolvetherestx26.00000208theother8rootsarecomplex(4pairsofconjugatedcomplexroots)ifits(x33x2+1)(x6)+4=(x33x2+1)(x6)16wecan:(x33x2+1)(x6)=21(x+1)(x310x2+28x27)=0x1=1x2=103+2095433763+20954+33763x3=103+(1232i)2095433763+(12+32i)20954+33763x4=103+(12+32i)2095433763+(1232i)20954+33763
Commented by minh2001 last updated on 04/Jul/19
No,you were wrong .Why  you set x^3  but not x^9 .I′ve  found other 8 solutions as  your mean,thank you
No,youwerewrong.Whyyousetx3butnotx9.Ivefoundother8solutionsasyourmean,thankyou
Commented by MJS last updated on 04/Jul/19
so show us how you found them  I can approximate them all
soshowushowyoufoundthemIcanapproximatethemall
Commented by MJS last updated on 04/Jul/19
with x^9   x_1 =−1  x_2 ≈6.00000208383  x_(3, 4) ≈−.994927692081±.650751638656i  x_(5, 6) ≈−.262576070729±1.25073913893i  x_(7, 8) ≈.684103814572±1.04916880346i  x_(9, 10) ≈1.07339890633±.300735402858i
withx9x1=1x26.00000208383x3,4.994927692081±.650751638656ix5,6.262576070729±1.25073913893ix7,8.684103814572±1.04916880346ix9,101.07339890633±.300735402858i

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