Question Number 120154 by mathace last updated on 29/Oct/20

Answered by mr W last updated on 29/Oct/20
![((8/7))^x =25(x−((17)/(25))) ((8/7))^(x−((17)/(25))) =25((8/7))^(−((17)/(25))) (x−((17)/(25))) e^((x−((17)/(25)))ln (8/7)) =25((8/7))^(−((17)/(25))) (x−((17)/(25))) −(1/(25))((8/7))^((17)/(25)) ln (8/7)=(((17)/(25))−x)(ln (8/7))e^((((17)/(25))−x)ln (8/7)) W[−(1/(25))((8/7))^((17)/(25)) ln (8/7)]=(((17)/(25))−x)ln (8/7) ⇒x=((17)/(25))−(1/(ln (8/7)))W[−(1/(25))((8/7))^((17)/(25)) ln (8/7)] ≈ { ((0.724057)),((53.864856)) :}](https://www.tinkutara.com/question/Q120179.png)
Commented by mathace last updated on 30/Oct/20

Commented by mathace last updated on 30/Oct/20

Commented by mr W last updated on 30/Oct/20
