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Solve-x-1-2x-2-3x-3-0-2x-1-4x-2-2x-3-2-3x-1-6x-2-4x-3-3-

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Question Number 180446 by Mastermind last updated on 12/Nov/22
Solve : x_1 + 2x_2 − 3x_3 = 0 2x_1 + 4x_2 − 2x_3 = 2 3x_1 + 6x_2 − 4x_3 = 3
Solve:x1+2x2−3x3=02x1+4x2−2x3=23x1+6x2−4x3=3
Answered by liuxinnan last updated on 12/Nov/22
Commented by liuxinnan last updated on 12/Nov/22
Answered by mr W last updated on 12/Nov/22
from eqn. (i) we get: 2x_1 +4x_2 =6x_3 ...(iv) from (ii) and (iv): 6x_3 =2+2x_3 ⇒x_3 =(1/2) from eqn. (i) we get: 3x_1 +6x_2 =9x_3 ...(v) from (iii) and (v): 9x_3 =3+4x_3 ⇒x_3 =(3/5) this is contradiction to x_3 =(1/2). that means the eqn. system has no solution.
fromeqn.(i)weget:2x1+4x2=6x3…(iv)from(ii)and(iv):6x3=2+2x3⇒x3=12fromeqn.(i)weget:3x1+6x2=9x3…(v)from(iii)and(v):9x3=3+4x3⇒x3=35thisiscontradictiontox3=12.thatmeanstheeqn.systemhasnosolution.

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