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Solve-x-1-x-2-4-




Question Number 170868 by Tawa11 last updated on 01/Jun/22
Solve:   ∣x   −   1∣    +   ∣x    −   2∣    ≥    4
Solve:x1+x24
Answered by thfchristopher last updated on 02/Jun/22
⇒∣x−1∣≥4−∣x−2∣  ⇒x−1≥4−∣x−2∣  or  x−1≤∣x−2∣−4  Case 1:  x−1≥4−∣x−2∣  ⇒∣x−2∣≥5−x  ⇒x−2≥5−x  or x−2≤x−5 (rejected)  ⇒2x≥7  ⇒x≥(7/2)  Case 2:  x−1≤∣x−2∣−4  ⇒∣x−2∣≥x+3  ⇒x−2≥x+3 (rejected) or x−2≤−x−3  ⇒2x≤−1  ⇒x≤−(1/2)  Conclusion: x≤−(1/2)  or  x≥(7/2)
⇒∣x1∣⩾4x2x14x2orx1⩽∣x24Case1:x14x2⇒∣x2∣⩾5xx25xorx2x5(rejected)2x7x72Case2:x1⩽∣x24⇒∣x2∣⩾x+3x2x+3(rejected)orx2x32x1x12Conclusion:x12orx72
Commented by Tawa11 last updated on 02/Jun/22
God bless you sir.
Godblessyousir.

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