Menu Close

solve-x-1-x-2-7x-3-dx-




Question Number 161101 by bounhome last updated on 12/Dec/21
solve:     ∫((x+1)/(x^2 −7x−3))dx
solve:x+1x27x3dx
Answered by FongXD last updated on 12/Dec/21
=(1/2)∫((2x−7+9)/(x^2 −7x−3))dx  =(1/2)∫((2x−7)/(x^2 −7x−3))dx+(9/2)∫(dx/(x^2 −7x−3))  =(1/2)ln∣x^2 −7x−3∣+(9/2)∫(dx/((x−(7/2))^2 −((61)/4)))  =(1/2)ln∣x^2 −7x−3∣+(9/2)∫(dx/((x−(7/2)−((√(61))/2))(x−(7/2)+((√(61))/2))))  =(1/2)ln∣x^2 −7x−3∣+(9/(2(√(61))))∫((1/(x−(7/2)−((√(61))/2)))−(1/(x−(7/2)+((√(61))/2))))dx  =(1/2)ln∣x^2 −7x−3∣+((9(√(61)))/(122))ln∣((2x−7−(√(61)))/(2x−7+(√(61))))∣+c, c∈R
=122x7+9x27x3dx=122x7x27x3dx+92dxx27x3=12lnx27x3+92dx(x72)2614=12lnx27x3+92dx(x72612)(x72+612)=12lnx27x3+9261(1x726121x72+612)dx=12lnx27x3+961122ln2x7612x7+61+c,cR

Leave a Reply

Your email address will not be published. Required fields are marked *