Menu Close

solve-x-2-3-2-x-3-




Question Number 174269 by mr W last updated on 28/Jul/22
solve (x^2 −3)^2 =x+3
solve(x23)2=x+3
Answered by Frix last updated on 28/Jul/22
obviously x=1∨x=−2 the other 2 are easy
obviouslyx=1x=2theother2areeasy
Answered by mr W last updated on 28/Jul/22
(x^2 −3)^2 −3=x  let x^2 −3=t   ...(i)  ⇒t^2 −3=x   ...(ii)  (i)−(ii):  x^2 −t^2 =t−x  (t−x)(t+x+1)=0  ⇒t−x=0  ⇒x^2 −x−3=0  ⇒x=((1±(√(13)))/2)  ⇒t+x+1=0  ⇒x^2 +x−2=0  ⇒x=−2 or 1
(x23)23=xletx23=t(i)t23=x(ii)(i)(ii):x2t2=tx(tx)(t+x+1)=0tx=0x2x3=0x=1±132t+x+1=0x2+x2=0x=2or1
Commented by Tawa11 last updated on 28/Jul/22
Great sir
Greatsir

Leave a Reply

Your email address will not be published. Required fields are marked *