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solve-x-3-3x-2-1-




Question Number 24663 by NECx last updated on 24/Nov/17
solve ∣x−3∣=∣3x+2∣−1
solvex3∣=∣3x+21
Answered by ajfour last updated on 24/Nov/17
Case I:       x < −(2/3)  , then       3−x = −3x−2−1  or    2x =−6         ⇒  x=−3  Case II:       −(2/3) < x < 3       3−x = 3x+2−1  or     4x=2      ⇒  x = (1/2) .  Case III:      x > 3      x−3 = 3x+2−1    or    2x =−4     ⇒  x=−2   but this is not within considered  interval so gets rejected.  So finally    x= −3, (1/2) .
CaseI:x<23,then3x=3x21or2x=6x=3CaseII:23<x<33x=3x+21or4x=2x=12.CaseIII:x>3x3=3x+21or2x=4x=2butthisisnotwithinconsideredintervalsogetsrejected.Sofinallyx=3,12.
Commented by NECx last updated on 25/Nov/17
thanks boss
thanksboss

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