Question Number 119503 by liberty last updated on 25/Oct/20
$${solve}\:\lfloor\:\sqrt{{x}}\:\rfloor\:=\:\lfloor\:\sqrt[{\mathrm{3}\:}]{{x}}\:\rfloor\: \\ $$
Answered by 1549442205PVT last updated on 25/Oct/20
$$\mathrm{Graph}\:\mathrm{two}\:\mathrm{functions}\:\mathrm{y}=\left[\:^{\mathrm{3}} \sqrt{\mathrm{x}}\right]\mathrm{and} \\ $$$$\mathrm{y}=\left[\:\sqrt{\mathrm{x}}\right]\mathrm{on}\:\mathrm{the}\:\mathrm{same}\:\:\mathrm{coordinate}\:\mathrm{system} \\ $$$$\:\mathrm{Oxy}\:\mathrm{we}\:\mathrm{get}\:\mathrm{the}\:\mathrm{solutions}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{given}\:\mathrm{equation}\:\mathrm{are}: \\ $$$$\mathrm{x}\in\left[\mathrm{0},\mathrm{1}\right)\cup\left[\mathrm{1},\mathrm{4}\right)\cup\left[\mathrm{8},\mathrm{9}\right)\Leftrightarrow\mathrm{x}\in\left[\mathrm{0},\mathrm{4}\right)\cup\left[\mathrm{8},\mathrm{9}\right) \\ $$
Answered by arkanmath7@gmail.com last updated on 06/Nov/20