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Question Number 116779 by mathdave last updated on 06/Oct/20
solve x^x =2
solvexx=2
Answered by Dwaipayan Shikari last updated on 06/Oct/20
xlogx=log(2) logxe^(logx) =log(2) logx=W_0 (log(2)) x=e^(W_0 (log(2))) =1.559610
xlogx=log(2)logxelogx=log(2)logx=W0(log(2))x=eW0(log(2))=1.559610

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