Question Number 171772 by Mikenice last updated on 20/Jun/22
$${solve}: \\ $$$${x}^{{x}} =\mathrm{27}{x}^{\mathrm{2}} .\:{find}\:{x} \\ $$
Commented by mr W last updated on 21/Jun/22
$${you}\:{can}\:{only}\:{approximate}. \\ $$$${x}\approx\mathrm{0}.\mathrm{165813},\:\mathrm{4}.\mathrm{270339} \\ $$