solve-x-x-x-1-4-1-x-

Question Number 171927 by Mikenice last updated on 21/Jun/22

s o l v e :

x^{\sqrt{x}} = {(\sqrt[4]{x})}^{1 + \sqrt{x}}

Answered by aleks041103 last updated on 22/Jun/22

x^{\sqrt{x}} = x^{\frac{1 + \sqrt{x}}{4}}

\Rightarrow \sqrt{x} = \frac{1}{4} + \frac{\sqrt{x}}{4}

\Rightarrow \sqrt{x} = \frac{1}{3}

\Rightarrow x = \frac{1}{9}

Commented by mr W last updated on 22/Jun/22

x = 1 a s w e l l

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