solve-y-2-x-2-sin-pi-2-pi-2-

Question Number 103859 by 175mohamed last updated on 17/Jul/20

s o l v e :

y^{2} + x^{2} = - \sin (θ) ., \frac{π}{2} ⩾ θ ⩾ - \frac{π}{2}

Answered by mathmax by abdo last updated on 18/Jul/20

if x and y from C let x = rcos α and y = r \sin α

e \Rightarrow r^{2} = - \sin θ but r > 0 (radius) \Rightarrow \sin θ < 0 \Rightarrow - \frac{π}{2} < θ < 0 \Rightarrow

r = \sqrt{- \sin θ} \Rightarrow x = \sqrt{- \sin θ} \cos (α) and y = \sqrt{- \sin θ} \sin (α) and \in] 0, 2 π [

if \sin θ > 0 \to no solution \dots

Commented by mathmax by abdo last updated on 18/Jul/20

sorry x and y from R . .