Menu Close

solve-y-sin-2x-y-sinx-x-




Question Number 99455 by mathmax by abdo last updated on 21/Jun/20
solve y^(′′)  −sin(2x)y^′    =((sinx)/x)
$$\mathrm{solve}\:\mathrm{y}^{''} \:−\mathrm{sin}\left(\mathrm{2x}\right)\mathrm{y}^{'} \:\:\:=\frac{\mathrm{sinx}}{\mathrm{x}} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *