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solve-y-y-y-e-t-ch-2-t-

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Question Number 90971 by abdomathmax last updated on 27/Apr/20
solve y^(′′) +y^′ +y =(e^(−t) /(ch^2 t))
$${solve}\:{y}^{''} \:+{y}^{'} \:+{y}\:=\frac{{e}^{−{t}} }{{ch}^{\mathrm{2}} {t}} \\ $$

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