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sove-inside-Z-3Z-the-systeme-5x-7y-10-2x-5y-8-




Question Number 62439 by mathsolverby Abdo last updated on 21/Jun/19
sove inside Z/3Z the systeme   { ((5x+7y =10)),((2x+5y =8)) :}
soveinsideZ/3Zthesysteme{5x+7y=102x+5y=8
Commented by arcana last updated on 22/Jun/19
Z/3Z=Z_3 ={0^� ,1^� ,2^� }  0^� ={...,−9,−6,−3,0,3,6,9,...}  1^� ={...,−10,−7,−4,1,4,7,10,...}  2^� ={...,−11,−8,−5,2,5,8,11,...}    2^� x+1^� y=1^�   2^� x+2^� y=2^�     ⇒2^� y−y=2^� −1^� =1^�   y=1^� ⇒2^� x+(1^� )=1^�   2^� x=0^�  (cancelativ)⇒x=0^�  cause (Z_3 ,+^� ,∙^� ) is a field
Z/3Z=Z3={0¯,1¯,2¯}0¯={,9,6,3,0,3,6,9,}1¯={,10,7,4,1,4,7,10,}2¯={,11,8,5,2,5,8,11,}2¯x+1¯y=1¯2¯x+2¯y=2¯2¯yy=2¯1¯=1¯y=1¯2¯x+(1¯)=1¯2¯x=0¯(cancelativ)x=0¯cause(Z3,+¯,¯)isafield

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