Question Number 42036 by Tawa1 last updated on 17/Aug/18

Commented by maxmathsup by imad last updated on 17/Aug/18
![a) g(θ) =−(3/4)sin(2θ) we have g(θ+π) =−(3/4)sin(2(θ+π)) =−(3/4)sin(2θ +2π) =−(3/4)sin(2θ) =g(θ) ⇒ g periodic with T=π we can study the variation on [−(π/2),(π/2)] but g(−θ) =(3/4)sin(2θ)=−g(θ) ⇒ g is odd so we can study the variation on [0,(π/2)] =[0,(π/4)]∪[(π/4),(π/2)] g^′ (θ) =−(3/2)cos(2θ) we have 2θ ∈[0,π] x 0 (π/4) (π/2) we have g(o)=0 , g((π/4))=−(3/4) g^′ (x) − + g((π/2)) =0 .... g(x) decr inc](https://www.tinkutara.com/question/Q42047.png)
Commented by tanmay.chaudhury50@gmail.com last updated on 17/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 17/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 17/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 17/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 17/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 17/Aug/18

Commented by Tawa1 last updated on 17/Aug/18

Commented by Tawa1 last updated on 17/Aug/18

Commented by Tawa1 last updated on 17/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 17/Aug/18

Commented by Tawa1 last updated on 17/Aug/18

Commented by Tawa1 last updated on 17/Aug/18
