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study-the-nature-of-sequence-u-n-u-0-1-and-u-n-1-1-u-n-e-n-




Question Number 28436 by abdo imad last updated on 25/Jan/18
study the nature of sequence (u_n ) / u_0 =1 and  u_(n+1) =  (1/(u_(n ) + e^(−n) )) .
$${study}\:{the}\:{nature}\:{of}\:{sequence}\:\left({u}_{{n}} \right)\:/\:{u}_{\mathrm{0}} =\mathrm{1}\:{and} \\ $$$${u}_{{n}+\mathrm{1}} =\:\:\frac{\mathrm{1}}{{u}_{{n}\:} +\:{e}^{−{n}} }\:. \\ $$

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