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suppose-one-of-the-side-of-any-box-that-can-be-carried-onto-an-airplane-must-be-less-than-8m-Find-the-maximum-value-of-such-a-box-if-the-sum-of-the-three-sides-can-not-exceed-46m-




Question Number 28199 by NECx last updated on 21/Jan/18
suppose one of the side of any  box that can be carried onto an  airplane must be less than 8m.  Find the maximum value of such  a box if the sum of the three sides  can not exceed 46m.
$${suppose}\:{one}\:{of}\:{the}\:{side}\:{of}\:{any} \\ $$$${box}\:{that}\:{can}\:{be}\:{carried}\:{onto}\:{an} \\ $$$${airplane}\:{must}\:{be}\:{less}\:{than}\:\mathrm{8}{m}. \\ $$$${Find}\:{the}\:{maximum}\:{value}\:{of}\:{such} \\ $$$${a}\:{box}\:{if}\:{the}\:{sum}\:{of}\:{the}\:{three}\:{sides} \\ $$$${can}\:{not}\:{exceed}\:\mathrm{46}{m}. \\ $$
Answered by mrW2 last updated on 22/Jan/18
V_(max) =a_(max) b_(max) c_(max) =8×8×8=512 m^3   8+8+8=24 m<46 m    Question seems to have a mistake.
$${V}_{{max}} ={a}_{{max}} {b}_{{max}} {c}_{{max}} =\mathrm{8}×\mathrm{8}×\mathrm{8}=\mathrm{512}\:{m}^{\mathrm{3}} \\ $$$$\mathrm{8}+\mathrm{8}+\mathrm{8}=\mathrm{24}\:{m}<\mathrm{46}\:{m} \\ $$$$ \\ $$$${Question}\:{seems}\:{to}\:{have}\:{a}\:{mistake}. \\ $$

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