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Suppose-that-you-wish-to-fabricate-a-uniform-wire-out-of-1-gram-of-copper-If-the-wire-is-to-have-a-resistance-of-R-0-5-and-all-of-the-copper-is-to-be-used-What-will-be-i-the-length-and-ii-the-diamet




Question Number 41443 by Necxx last updated on 07/Aug/18
Suppose that you wish to fabricate  a uniform wire out of 1 gram of  copper.If the wire is to have a  resistance of R=0.5Ω,and all of  the copper is to be used.What will  be(i)the length and (ii)the diameter  of the wire.
Supposethatyouwishtofabricateauniformwireoutof1gramofcopper.IfthewireistohavearesistanceofR=0.5Ω,andallofthecopperistobeused.Whatwillbe(i)thelengthand(ii)thediameterofthewire.
Answered by tanmay.chaudhury50@gmail.com last updated on 07/Aug/18
m=Πr^2 ld    r=radius of wire                           l=length of wire                           d=density of wire                           ρ=resistivity of wire                           R=resistance of wire                           m=mass of wire  R=((ρl)/(Πr^2 ))  m.R=d.ρ.l^2   l=(√((m.R)/(d.ρ)))    r^2 =(m/(Πld))    r^2 =(m/(Πd.))×(√((d.ρ)/(m.R))) =(1/Π).(√((m.ρ)/(d.R)))   r=(1/( (√Π)))×(((m.ρ)/(d.R)))^(1/4)   dia=(2/( (√Π)))×(((m.ρ)/(d.R)))^(1/4)
m=Πr2ldr=radiusofwirel=lengthofwired=densityofwireρ=resistivityofwireR=resistanceofwirem=massofwireR=ρlΠr2m.R=d.ρ.l2l=m.Rd.ρr2=mΠldr2=mΠd.×d.ρm.R=1Π.m.ρd.Rr=1Π×(m.ρd.R)14dia=2Π×(m.ρd.R)14
Commented by Necxx last updated on 07/Aug/18
yeah....Thanks
yeah.Thanks

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