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Suppose-your-weight-is-50kg-and-you-are-taking-rest-what-is-the-de-brogli-wavelength-associated-by-you-Respect-to-the-universal-system-suppose-another-one-who-is-calculating-your-wavelength-is-on

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Question Number 99537 by Dwaipayan Shikari last updated on 21/Jun/20
Suppose your weight is 50kg and you are taking rest. what is the de-brogli wavelength associated by you. (Respect to the universal system)[suppose another one who is calculating your wavelength is on space]
$$\mathrm{Suppose}\:\mathrm{your}\:\mathrm{weight}\:\mathrm{is}\:\mathrm{50kg}\:\mathrm{and}\:\mathrm{you}\:\mathrm{are}\:\mathrm{taking}\:\mathrm{rest}. \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{de}-{brogli}\:\mathrm{wavelength}\:\mathrm{associated}\:\mathrm{by}\:\mathrm{you}. \\ $$$$\left(\mathrm{Respect}\:\mathrm{to}\:\mathrm{the}\:\mathrm{universal}\:\mathrm{system}\right)\left[\mathrm{suppose}\:\mathrm{another}\:\mathrm{one}\:\mathrm{who}\:\mathrm{is}\:\right. \\ $$$$\left.\mathrm{calculating}\:\mathrm{your}\:\mathrm{wavelength}\:\mathrm{is}\:\mathrm{on}\:\mathrm{space}\right] \\ $$
Answered by smridha last updated on 21/Jun/20
meaningless question.. weight=50 kg!! that′s not right it should be mass. de−broglie formula valid for quantum world... are you quantum particle?? wavelength is very negligible. and also you are in rest..so it′s meaningless..to use de −broglie.
$$\boldsymbol{{meaningless}}\:\boldsymbol{{question}}.. \\ $$$$\boldsymbol{{weight}}=\mathrm{50}\:\boldsymbol{{kg}}!!\:\boldsymbol{{that}}'\boldsymbol{{s}}\:\boldsymbol{{not}}\:\boldsymbol{{right}} \\ $$$$\boldsymbol{{it}}\:\boldsymbol{{should}}\:\boldsymbol{{be}}\:\boldsymbol{{mass}}. \\ $$$$\boldsymbol{{de}}−\boldsymbol{{broglie}}\:\boldsymbol{{formula}}\:\boldsymbol{{valid}}\:\boldsymbol{{for}} \\ $$$$\boldsymbol{{quantum}}\:\:\boldsymbol{{world}}… \\ $$$$\boldsymbol{{are}}\:\boldsymbol{{you}}\:\boldsymbol{{quantum}}\:\boldsymbol{{particle}}?? \\ $$$$\boldsymbol{{wavelength}}\:\boldsymbol{{is}}\:\boldsymbol{{very}}\:\boldsymbol{{negligible}}. \\ $$$$\boldsymbol{{and}}\:\boldsymbol{{also}}\:\boldsymbol{{you}}\:\boldsymbol{{are}}\:\boldsymbol{{in}}\:\boldsymbol{{rest}}..\boldsymbol{{so}}\:\boldsymbol{{it}}'{s} \\ $$$$\boldsymbol{{meaningless}}..{to}\:\boldsymbol{{use}}\:\boldsymbol{{de}}\:−\boldsymbol{{brogli}}{e}. \\ $$
Commented by Dwaipayan Shikari last updated on 21/Jun/20
Earth is rotating about his axis with a speed of 30km/s(approx)
$${Earth}\:{is}\:{rotating}\:{about}\:{his}\:{axis}\:{with}\:{a}\:{speed}\:{of}\:\mathrm{30}{km}/{s}\left({approx}\right) \\ $$
Commented by Dwaipayan Shikari last updated on 21/Jun/20
Sorry! It is mass .I used the usual speech like weight.
$${Sorry}!\:{It}\:{is}\:{mass}\:.{I}\:{used}\:{the}\:{usual}\:{speech}\:{like}\:{weight}. \\ $$
Commented by smridha last updated on 21/Jun/20
earth also moves round the sun at a speed v=(√(gr))..and we also don′t know the velocity of frame where we measure.. and the most important thing can we use de−broglie formula in that case..because we are not quantum particle...
$$\boldsymbol{{earth}}\:\boldsymbol{{also}}\:\boldsymbol{{moves}}\:\boldsymbol{{round}}\:\boldsymbol{{the}}\:\boldsymbol{{sun}} \\ $$$$\boldsymbol{{at}}\:\boldsymbol{{a}}\:\boldsymbol{{speed}}\:\boldsymbol{{v}}=\sqrt{\boldsymbol{{gr}}}..\boldsymbol{{and}}\: \\ $$$$\boldsymbol{{we}}\:\boldsymbol{{also}}\:\boldsymbol{{don}}'{t}\:\boldsymbol{{know}}\:\boldsymbol{{the}}\:\boldsymbol{{velocity}} \\ $$$$\boldsymbol{{of}}\:\boldsymbol{{frame}}\:\boldsymbol{{where}}\:\boldsymbol{{we}}\:\boldsymbol{{measure}}.. \\ $$$$\boldsymbol{{and}}\:\:\boldsymbol{{the}}\:\boldsymbol{{most}}\:\boldsymbol{{important}}\:\boldsymbol{{thing}} \\ $$$$\boldsymbol{{can}}\:\boldsymbol{{we}}\:\boldsymbol{{use}}\:\boldsymbol{{de}}−\boldsymbol{{broglie}}\:\boldsymbol{{formula}} \\ $$$$\boldsymbol{{in}}\:\boldsymbol{{that}}\:\boldsymbol{{case}}..\boldsymbol{{because}}\:\boldsymbol{{we}}\:\boldsymbol{{are}}\:\boldsymbol{{not}} \\ $$$$\boldsymbol{{quantum}}\:\boldsymbol{{particle}}… \\ $$$$ \\ $$
Commented by Dwaipayan Shikari last updated on 21/Jun/20
suppose the frame is inertial
$${suppose}\:{the}\:{frame}\:{is}\:{inertial} \\ $$
Commented by Dwaipayan Shikari last updated on 21/Jun/20
I also know it is a stupid question. But i am trying to visualise those things
$${I}\:{also}\:{know}\:{it}\:{is}\:{a}\:{stupid}\:{question}.\:{But}\:{i}\:{am}\:{trying}\:{to}\:{visualise}\:{those}\:{things} \\ $$
Commented by Dwaipayan Shikari last updated on 21/Jun/20
I am sorry as i am spending your valuable time.
$${I}\:{am}\:{sorry}\:{as}\:{i}\:{am}\:{spending}\:{your}\:{valuable}\:{time}. \\ $$
Commented by Dwaipayan Shikari last updated on 21/Jun/20
I am a student so i want to learn more.
$${I}\:{am}\:{a}\:{student}\:{so}\:{i}\:{want}\:{to}\:{learn}\:{more}. \\ $$
Commented by smridha last updated on 22/Jun/20
well I consider it is a non−Relativistic case... then if the frame(lets say s^′ ) is inertial to our lab−frame then the observer who watching over you from s^′ , see you are standing still in rest. so relative velocity v_(rel) =0 so your de−broglie wavelength is 𝛌⇒∞.I am not satisfied with this ans...are you???it′s fail to describe the physical nature... because ∞ is just a concept it cannot be ans..no one can know what it is..
$$\boldsymbol{{well}}\:\boldsymbol{{I}}\:\boldsymbol{{consider}}\:\boldsymbol{{it}}\:\boldsymbol{{is}}\:\boldsymbol{{a}}\:\boldsymbol{{non}}−\boldsymbol{{R}}{e}\boldsymbol{{lativistic}} \\ $$$$\boldsymbol{{case}}… \\ $$$$\boldsymbol{{then}}\:\boldsymbol{{if}}\:\boldsymbol{{the}}\:\boldsymbol{{frame}}\left(\boldsymbol{{lets}}\:\boldsymbol{{say}}\:\boldsymbol{{s}}^{'} \right)\:\boldsymbol{{is}}\:\boldsymbol{{inertial}} \\ $$$$\boldsymbol{{to}}\:\boldsymbol{{our}}\:\boldsymbol{{lab}}−\boldsymbol{{frame}}\:\boldsymbol{{then}}\:\boldsymbol{{the}}\:\boldsymbol{{observer}} \\ $$$$\boldsymbol{{who}}\:\boldsymbol{{watching}}\:\boldsymbol{{over}}\:\boldsymbol{{you}}\:\boldsymbol{{from}}\:\boldsymbol{{s}}^{'} , \\ $$$$\boldsymbol{{see}}\:\boldsymbol{{you}}\:\boldsymbol{{are}}\:\boldsymbol{{standing}}\:\boldsymbol{{still}}\:\boldsymbol{{in}}\:\boldsymbol{{rest}}. \\ $$$$\boldsymbol{{so}}\:\boldsymbol{{relative}}\:\boldsymbol{{velocity}}\:\boldsymbol{{v}}_{\boldsymbol{{rel}}} =\mathrm{0} \\ $$$$\boldsymbol{{so}}\:\boldsymbol{{your}}\:\boldsymbol{{de}}−\boldsymbol{{broglie}}\:\boldsymbol{{wavelength}} \\ $$$$\boldsymbol{{is}}\:\boldsymbol{\lambda}\Rightarrow\infty.\boldsymbol{{I}}\:\boldsymbol{{am}}\:\boldsymbol{{not}}\:\boldsymbol{{satisfied}}\:\boldsymbol{{with}} \\ $$$$\boldsymbol{{this}}\:\boldsymbol{{ans}}…\boldsymbol{{are}}\:\boldsymbol{{you}}???\boldsymbol{{it}}'{s}\:\boldsymbol{{fail}}\:\boldsymbol{{to}} \\ $$$$\boldsymbol{{describe}}\:\boldsymbol{{the}}\:\boldsymbol{{physical}}\:\boldsymbol{{nature}}… \\ $$$$\boldsymbol{{because}}\:\infty\:\boldsymbol{{is}}\:\boldsymbol{{just}}\:\boldsymbol{{a}}\:\boldsymbol{{concept}}\:\boldsymbol{{it}}\:\boldsymbol{{cannot}} \\ $$$$\boldsymbol{{be}}\:\boldsymbol{{ans}}..\boldsymbol{{no}}\:\boldsymbol{{one}}\:\boldsymbol{{can}}\:\boldsymbol{{know}}\:\boldsymbol{{what}} \\ $$$$\boldsymbol{{it}}\:\boldsymbol{{is}}.. \\ $$
Commented by Dwaipayan Shikari last updated on 22/Jun/20
But respect to the inertial frame I was moving at a speed of 30 km/s. And at an instant of time earth revolving speed may be neglected
Commented by smridha last updated on 22/Jun/20
what is inertial frame of reference??? (i)a frane which is moving with uniform velocity (ii)a frame which is stanting at rest and another frame is moving with constant speed respect to that frame..in that case 1st frame is also a inertial frame. I consider a frame which has uniform velocity as same as earth. rotational speed about its own axies and revolvig speed around the sun both in this case are same as earth. so from this assumtion you also at rest for the prime observer who is watching over you. so v_(rel) =0 so 𝛌⇒∞..worthless!! for simplification you can consider a frame of reference like a geostationary satelite.
$$\boldsymbol{{what}}\:\boldsymbol{{is}}\:\boldsymbol{{inertial}}\:\boldsymbol{{frame}}\:\boldsymbol{{of}}\:\boldsymbol{{reference}}??? \\ $$$$\left(\boldsymbol{{i}}\right)\boldsymbol{{a}}\:\boldsymbol{{frane}}\:\boldsymbol{{which}}\:\boldsymbol{{is}}\:\boldsymbol{{moving}}\:\boldsymbol{{with}} \\ $$$$\boldsymbol{{uniform}}\:\boldsymbol{{velocity}} \\ $$$$\left(\boldsymbol{{ii}}\right)\boldsymbol{{a}}\:\boldsymbol{{frame}}\:\boldsymbol{{which}}\:\boldsymbol{{is}}\:\boldsymbol{{stanting}} \\ $$$$\boldsymbol{{at}}\:\boldsymbol{{rest}}\:\boldsymbol{{and}}\:\boldsymbol{{another}}\:\boldsymbol{{frame}}\:\boldsymbol{{is}}\: \\ $$$$\boldsymbol{{moving}}\:\boldsymbol{{with}}\:\boldsymbol{{constant}}\:\boldsymbol{{speed}}\:\boldsymbol{{respect}} \\ $$$$\boldsymbol{{to}}\:\boldsymbol{{that}}\:\boldsymbol{{frame}}..\boldsymbol{{in}}\:\boldsymbol{{that}}\:\boldsymbol{{case}}\:\mathrm{1}\boldsymbol{{st}}\:\boldsymbol{{frame}} \\ $$$$\boldsymbol{{is}}\:\boldsymbol{{also}}\:\boldsymbol{{a}}\:\boldsymbol{{inertial}}\:\boldsymbol{{frame}}. \\ $$$$\boldsymbol{{I}}\:\boldsymbol{{consider}}\:\boldsymbol{{a}}\:\boldsymbol{{frame}}\:\boldsymbol{{which}}\:\boldsymbol{{has}} \\ $$$$\boldsymbol{{uniform}}\:\boldsymbol{{velocity}}\:\boldsymbol{{as}}\:\boldsymbol{{same}}\:\boldsymbol{{as}}\:\boldsymbol{{earth}}. \\ $$$$\boldsymbol{{rotational}}\:\boldsymbol{{speed}}\:\boldsymbol{{about}}\:\boldsymbol{{its}}\:\boldsymbol{{own}}\:\boldsymbol{{axies}}\:\boldsymbol{{and}} \\ $$$$\boldsymbol{{revolvig}}\:\boldsymbol{{speed}}\:\boldsymbol{{around}}\:\boldsymbol{{the}}\:\boldsymbol{{sun}}\:\boldsymbol{{both}} \\ $$$$\boldsymbol{{in}}\:\boldsymbol{{this}}\:\boldsymbol{{case}}\:\boldsymbol{{are}}\:\boldsymbol{{same}}\:\boldsymbol{{as}}\:\boldsymbol{{earth}}. \\ $$$$\boldsymbol{{so}}\:\boldsymbol{{from}}\:\boldsymbol{{this}}\:\boldsymbol{{assumtion}}\:\boldsymbol{{you}}\:\boldsymbol{{also}} \\ $$$$\boldsymbol{{at}}\:\boldsymbol{{rest}}\:\boldsymbol{{for}}\:\boldsymbol{{the}}\:\boldsymbol{{prime}}\:\boldsymbol{{observer}}\:\boldsymbol{{who}}\:\boldsymbol{{is}} \\ $$$$\boldsymbol{{watching}}\:\boldsymbol{{over}}\:\boldsymbol{{you}}. \\ $$$$\boldsymbol{{so}}\:\boldsymbol{{v}}_{\boldsymbol{{rel}}} =\mathrm{0}\:\boldsymbol{{so}}\:\boldsymbol{\lambda}\Rightarrow\infty..\boldsymbol{{worthless}}!! \\ $$$$\boldsymbol{{for}}\:\boldsymbol{{simplification}}\:\boldsymbol{{you}}\:\boldsymbol{{can}}\: \\ $$$$\boldsymbol{{consider}}\:\boldsymbol{{a}}\:\boldsymbol{{frame}}\:\boldsymbol{{of}}\:\boldsymbol{{reference}} \\ $$$$\boldsymbol{{like}}\:\boldsymbol{{a}}\:\boldsymbol{{geostationary}}\:\boldsymbol{{satelite}}. \\ $$
Commented by prakash jain last updated on 23/Jun/20
The laws of quantum physics apply to all objects regardless of mass.
$$\mathrm{The}\:\mathrm{laws}\:\mathrm{of}\:\mathrm{quantum}\:\mathrm{physics}\:\mathrm{apply} \\ $$$$\mathrm{to}\:\mathrm{all}\:\mathrm{objects}\:\mathrm{regardless}\:\mathrm{of}\:\mathrm{mass}. \\ $$
Commented by smridha last updated on 23/Jun/20
but it′s not logical to use because the result is very negligible...therefore physicists say classical mechanics is the approximation of quantum mechanics....if the result is same then there is no cause to devolope quantum mechanics.. you should aware of that in which context which formula do you use or not able to use.. classical and quantum both are important...physicists do not happy with some mathematical result but the significant mathematical result and so they give same priority to both mechanics...
$$\boldsymbol{{but}}\:\boldsymbol{{it}}'\boldsymbol{{s}}\:\boldsymbol{{not}}\:\boldsymbol{{logical}}\:\boldsymbol{{to}}\:\boldsymbol{{use}} \\ $$$$\boldsymbol{{because}}\:\boldsymbol{{the}}\:\boldsymbol{{result}}\:\boldsymbol{{is}}\:\:\boldsymbol{{very}} \\ $$$$\boldsymbol{{negligible}}…\boldsymbol{{therefore}}\: \\ $$$$\boldsymbol{{physicists}}\:\boldsymbol{{say}}\:\boldsymbol{{classical}}\:\boldsymbol{{mechanics}} \\ $$$$\boldsymbol{{is}}\:\boldsymbol{{the}}\:\boldsymbol{{approximation}}\:\boldsymbol{{of}}\:\boldsymbol{{quantum}} \\ $$$$\boldsymbol{{mechanics}}….\boldsymbol{{if}}\:\boldsymbol{{the}}\:\boldsymbol{{result}}\:\boldsymbol{{is}}\: \\ $$$$\boldsymbol{{same}}\:\boldsymbol{{then}}\:\boldsymbol{{there}}\:\boldsymbol{{is}}\:\boldsymbol{{no}}\:\boldsymbol{{cause}}\:\boldsymbol{{to}} \\ $$$$\boldsymbol{{devolope}}\:\boldsymbol{{quantum}}\:\boldsymbol{{mechanics}}.. \\ $$$$\boldsymbol{{you}}\:\boldsymbol{{should}}\:\boldsymbol{{aware}}\:\boldsymbol{{of}}\:\boldsymbol{{that}}\:\boldsymbol{{in}} \\ $$$$\boldsymbol{{which}}\:\boldsymbol{{context}}\:\boldsymbol{{which}}\:\boldsymbol{{formula}} \\ $$$$\boldsymbol{{do}}\:\boldsymbol{{you}}\:\boldsymbol{{use}}\:\boldsymbol{{or}}\:\boldsymbol{{not}}\:\boldsymbol{{able}}\:\boldsymbol{{to}}\:\boldsymbol{{use}}.. \\ $$$$\boldsymbol{{classical}}\:\boldsymbol{{and}}\:\boldsymbol{{quantum}}\:\boldsymbol{{both}} \\ $$$$\boldsymbol{{are}}\:\boldsymbol{{important}}…{phy}\boldsymbol{{sicists}}\:\boldsymbol{{do}}\:\boldsymbol{{not}} \\ $$$$\boldsymbol{{happy}}\:\boldsymbol{{with}}\:\boldsymbol{{some}}\:\boldsymbol{{mathematical}} \\ $$$$\boldsymbol{{result}}\:\boldsymbol{{but}}\:\boldsymbol{{the}}\:\boldsymbol{{significant}}\: \\ $$$$\boldsymbol{{mathematical}}\:\boldsymbol{{result}}\:\boldsymbol{{and}}\:\boldsymbol{{so}} \\ $$$$\boldsymbol{{they}}\:\boldsymbol{{give}}\:\boldsymbol{{same}}\:\boldsymbol{{pr}}{i}\boldsymbol{{ority}}\:\boldsymbol{{to}}\:\boldsymbol{{both}} \\ $$$$\boldsymbol{{mechanics}}… \\ $$
Commented by prakash jain last updated on 23/Jun/20
100% agree with you.
$$\mathrm{100\%}\:\mathrm{agree}\:\mathrm{with}\:\mathrm{you}. \\ $$

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