surface-du-rectangle-

Question Number 183628 by a.lgnaoui last updated on 27/Dec/22

s u r f a c e d u r e c t a n g l e ?

Commented by a.lgnaoui last updated on 27/Dec/22

Commented by Frix last updated on 27/Dec/22

a + 9 = b + 2 = r

\Rightarrow

b = a + 7 \land r = a + 9

a^{2} + b^{2} = r^{2}

a^{2} + {(a + 7)}^{2} = {(a + 9)}^{2}

a^{2} - 4 a - 32 = 0

(a - 8) (a + 4) = 0

\Rightarrow

a = 8 \land b = 15 \land r = 17

Area = 120

Answered by HeferH last updated on 27/Dec/22

{(R - 9)}^{2} + {(R - 2)}^{2} = R^{2}

R^{2} + 81 - 18 R + R^{2} + 4 - 4 R = R^{2}

R^{2} - 22 R + 85 = 0

(R - 5) (R - 17) = 0

R = 9 + \dots \Rightarrow R \neq 5

R = 17

A r e a = (17 - 9) (17 - 2) = 8 \cdot 15 = 120

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