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tan-2-20-o-tan-2-40-o-tan-2-80-o-




Question Number 85313 by john santu last updated on 20/Mar/20
tan^2 (20^o ) + tan^2 (40^o )+ tan^2 (80^o ) =
$$\mathrm{tan}\:^{\mathrm{2}} \left(\mathrm{20}^{\mathrm{o}} \right)\:+\:\mathrm{tan}\:^{\mathrm{2}} \left(\mathrm{40}^{\mathrm{o}} \right)+\:\mathrm{tan}\:^{\mathrm{2}} \left(\mathrm{80}^{\mathrm{o}} \right)\:= \\ $$
Answered by john santu last updated on 20/Mar/20

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