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tan-F-y-F-x-




Question Number 107764 by hhryhrry2 last updated on 12/Aug/20
             tanθ =  ((Σ F_y )/(Σ F_x ))
tanθ=ΣFyΣFx
Commented by ajfour last updated on 12/Aug/20
(dp^� /dt)=(√((ΣF_x )^2 +(ΣF_y )^2 )) (cos θi^� +sin θj^� )
dp¯dt=(ΣFx)2+(ΣFy)2(cosθi^+sinθj^)

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