tan3-tan2-1-find-the-general-solution-

Question Number 41902 by upadhyayrakhi20@gmail.com last updated on 15/Aug/18

\tan 3 θ \tan 2 θ = 1

find the general^{solution \dots \dots}

Answered by MJS last updated on 15/Aug/18

\tan 3 θ \tan 2 θ - 1 = 0

- 2 \frac{\cos 5 θ}{\cos 5 θ + \cos θ} = 0

(sorry no time for typing at the moment)

\cos 5 θ = 0 \land \cos 5 θ + \cos θ \neq 0

θ = \pm \frac{π}{10} + π z \lor θ = \pm \frac{3 π}{10} + π z; z \in Z

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