The-acceleration-vector-of-a-particle-in-uniform-circular-motion-averaged-over-one-cycle-is-a-null-vector-True-False-

Question Number 16502 by Tinkutara last updated on 23/Jun/17

The acceleration vector of a particle in

uniform circular motion averaged over

one cycle is a null vector . (True / False)

Answered by ajfour last updated on 23/Jun/17

\bar{a} = - \frac{v_{0}^{2}}{r} \hat{r} = - \frac{v_{0}^{2}}{r} (\cos θ \hat{i} + \sin θ \hat{j})

⟨ \bar{a} ⟩ = - \frac{v_{0}^{2}}{r} [⟨ \cos θ ⟩ \hat{i} + ⟨ \sin θ ⟩ \hat{j}]

= - \frac{v_{0}^{2}}{r} [0 \hat{i} + 0 \hat{j}] = 0

f o r △ θ = 2 n π .

Facebook Tweet Pin