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Question Number 78889 by gopikrishnan last updated on 21/Jan/20
the angle between the planes r^→ .(2i^→ +2j^→ +2k^→ )=4 and 4x−2y+2z=15 is
theanglebetweentheplanesr.(2i+2j+2k)=4and4x2y+2z=15is
Answered by Kunal12588 last updated on 21/Jan/20
π_1  : r^→ ∙(2i+2j+2k)=4  π_2 : r^→ ∙(4i−2j+2k)=15  you just have to find the angle between the  vectors (2i+2j+2k) and (4i−2j+2k).
π1:r(2i+2j+2k)=4π2:r(4i2j+2k)=15youjusthavetofindtheanglebetweenthevectors(2i+2j+2k)and(4i2j+2k).

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