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The-angle-between-the-planes-r-2i-2j-2k-4-and-4x-2y-2z-15-is-




Question Number 79054 by gopikrishnan last updated on 22/Jan/20
The angle between the planes r^→ .(2i^→ +2j^→ +2k^→ )=4 and 4x−2y+2z=15 is
$${The}\:{angle}\:{between}\:{the}\:{planes}\:\overset{\rightarrow} {{r}}.\left(\mathrm{2}\overset{\rightarrow} {{i}}+\mathrm{2}\overset{\rightarrow} {{j}}+\mathrm{2}\overset{\rightarrow} {{k}}\right)=\mathrm{4}\:{and}\:\mathrm{4}{x}−\mathrm{2}{y}+\mathrm{2}{z}=\mathrm{15}\:{is} \\ $$

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