The-characteristic-polynomial-matrices-1-2-3-4-5-6-7-8-9-is- Tinku Tara June 4, 2023 Matrices and Determinants 0 Comments FacebookTweetPin Question Number 54953 by gunawan last updated on 15/Feb/19 Thecharacteristicpolynomialmatrices[1−2345−6−789]is… Commented by maxmathsup by imad last updated on 16/Feb/19 det(A−xI)=|1−x−2345−x−6|∣−78−x9∣=(1−x)(9(5−x)+6(8−x))−4(−18−3(8−x))−7(12−3(5−x))=(1−x)(45−9x+48−6x)−4(−18−24+3x)−7(12−15+3x)=(1−x)(93−15x)−4(−42+3x)−7(−3+3x)=93−15x−93x+15x2+168−12x+21−21x=15x2−(93+27)x+93+168+21=25x2−120x+114+168=25x2−120x+282 Answered by kaivan.ahmadi last updated on 15/Feb/19 denomiatethismatricesbyA.f(x)=det(A−xI)=|1−x−2345−x−6−789−x|2R1+R2andsarrusrule|1−x−236−2x1−x0−789−x||1−x−236−2x1−x0−789−x|=[(1−x)2(9−x)+24(6−2x)]−[−21(1−x)−2(6−2x)(9−x)]=[(1−2x+x2)(9−x)+144−48x]−[21+21x−2(54−6x−18x+2x2]=[9−x−18x+2x2+9x2−x3+144−48x]−[21+21x−108+48x−4x2]=[−x3+11x2−67x+153]−[−4x2+69x−87]=−x3+15x2−136x+240 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-186026Next Next post: Let-vector-set-u-1-u-2-u-3-u-4-in-C-n-free-linear-So-that-u-1-u-2-u-2-u-3-u-3-u-4-u-4-u-1-too-free-linear-scalar-have-to- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.
![The characteristic polynomial matrices [(1,(−2),3),(4,5,(−6)),((−7),8,9) ]is...](https://www.tinkutara.com/question/Q54953.png)
![denomiate this matrices by A. f(x)=det(A−xI)= determinant (((1−x −2 3 )),((4 5−x −6)),((−7 8 9−x))) 2R_1 +R_2 and sarrus rule determinant (((1−x −2 3)),((6−2x 1−x 0)),((−7 8 9−x))) determinant (((1−x −2 3)),((6−2x 1−x 0)),((−7 8 9−x)))= [(1−x)^2 (9−x)+24(6−2x)]−[−21(1−x)−2(6−2x)(9−x)]= [(1−2x+x^2 )(9−x)+144−48x]−[21+21x−2(54−6x−18x+2x^2 ]= [9−x−18x+2x^2 +9x^2 −x^3 +144−48x]−[21+21x−108+48x−4x^2 ]= [−x^3 +11x^2 −67x+153]−[−4x^2 +69x−87]= −x^3 +15x^2 −136x+240](https://www.tinkutara.com/question/Q54959.png)