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Question Number 17524 by 786 last updated on 07/Jul/17
The circle ω touches the circle Ω  internally at P. The centre O of Ω is  outside ω. Let XY be a diameter of Ω  which is also tangent to ω. Assume  PY > PX. Let PY intersect ω at Z. If  YZ = 2PZ, what is the magnitude of  ∠PYX in degrees?
ThecircleωtouchesthecircleΩinternallyatP.ThecentreOofΩisoutsideω.LetXYbeadiameterofΩwhichisalsotangenttoω.AssumePY>PX.LetPYintersectωatZ.IfYZ=2PZ,whatisthemagnitudeofPYXindegrees?
Answered by ajfour last updated on 07/Jul/17
∠PYX=15° .
PYX=15°.
Commented by ajfour last updated on 07/Jul/17
Commented by ajfour last updated on 08/Jul/17
YZ=2PZ   or  3PZ=PY  3(2rcos θ)=2Rcos θ  ⇒    R=3r    In △OCN, sin 2θ=(r/(R−r)) =(r/(3r−r))       sin 2θ = (1/2)   or    θ=15° .
YZ=2PZor3PZ=PY3(2rcosθ)=2RcosθR=3rInOCN,sin2θ=rRr=r3rrsin2θ=12orθ=15°.
Commented by Tinkutara last updated on 07/Jul/17
Thanks Sir!
ThanksSir!

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