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The-curve-y-ax-2-bx-c-crosses-the-y-axis-at-the-point-0-3-and-has-stationary-point-at-1-2-Find-the-values-of-a-b-and-c-




Question Number 56749 by pete last updated on 22/Mar/19
The curve y=ax^2 +bx+c crosses the  y−axis at the point (0,3) and has  stationary point at (1,2). Find the  values of a,b and c.
Thecurvey=ax2+bx+ccrossestheyaxisatthepoint(0,3)andhasstationarypointat(1,2).Findthevaluesofa,bandc.
Answered by ajfour last updated on 22/Mar/19
c=3  2a(1)+b=0  2=a+b+3  ⇒2a+2=a+3   ⇒  a=1  and b=−2 .    y=x^2 −2x+3 .
c=32a(1)+b=02=a+b+32a+2=a+3a=1andb=2.y=x22x+3.

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