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The-curve-y-ax-b-2x-1-has-the-stationary-point-at-2-7-Find-the-value-of-a-and-b-




Question Number 52124 by 786786AM last updated on 03/Jan/19
The curve y = ax + (b/(2x− 1)) has the stationary point at  (2, 7) . Find the value of a and b .
Thecurvey=ax+b2x1hasthestationarypointat(2,7).Findthevalueofaandb.
Answered by tanmay.chaudhury50@gmail.com last updated on 03/Jan/19
2xy−y=2ax^2 −ax+b  partial derivative w.r.t x  2y−0=4ax−a  14=8a−a  a=7  y=ax+(b/(2x−1))  7=7×2+(b/(2×2−1))  (b/3)=−7  b=−21    pls check is it correct...
2xyy=2ax2ax+bpartialderivativew.r.tx2y0=4axa14=8aaa=7y=ax+b2x17=7×2+b2×21b3=7b=21plscheckisitcorrect

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