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the-distance-from-A-to-B-is-44km-the-speed-of-a-car-is-2kms-1-find-the-term-hence-the-amount-of-money-needed-to-buy-fuel-if-for-every-6km-10-l-of-fuel-is-used-which-causes-600-box-




Question Number 34170 by Rio Mike last updated on 01/May/18
the distance from A to B is 44km  the speed of a car is 2kms^(−1)  find   the term hence the amount of   money needed to buy fuel if for   every 6km 10 l of fuel is used which  causes 600 box.
$${the}\:{distance}\:{from}\:{A}\:{to}\:{B}\:{is}\:\mathrm{44}{km} \\ $$$${the}\:{speed}\:{of}\:{a}\:{car}\:{is}\:\mathrm{2}{kms}^{−\mathrm{1}} \:{find}\: \\ $$$${the}\:{term}\:{hence}\:{the}\:{amount}\:{of}\: \\ $$$${money}\:{needed}\:{to}\:{buy}\:{fuel}\:{if}\:{for}\: \\ $$$${every}\:\mathrm{6}{km}\:\mathrm{10}\:{l}\:{of}\:{fuel}\:{is}\:{used}\:{which} \\ $$$${causes}\:\mathrm{600}\:{box}. \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 02/May/18
time=((44)/2)=22seconds  fuel=((10)/6)×44=((440)/6)litrs  expenditure=((440)/6)×600=44000 bucks
$${time}=\frac{\mathrm{44}}{\mathrm{2}}=\mathrm{22}{seconds} \\ $$$${fuel}=\frac{\mathrm{10}}{\mathrm{6}}×\mathrm{44}=\frac{\mathrm{440}}{\mathrm{6}}{litrs} \\ $$$${expenditure}=\frac{\mathrm{440}}{\mathrm{6}}×\mathrm{600}=\mathrm{44000}\:{bucks} \\ $$

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