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The-eriodic-time-of-a-simple-pendulum-is-given-by-T-2pi-L-g-if-L-100-0-1cm-s-e-and-the-time-s-for-10-ossilations-are-48-2-48-2-48-7-48-5-48-4-48-2-48-4-48-6-48-5-48-2-calcukate-g-and-the-stand




Question Number 29260 by NECx last updated on 06/Feb/18
The eriodic time of a simple  pendulum is given by T=2π(√(L/g)).  if L=100±0.1cm(s.e) and the  time s for 10 ossilations are:  48.2,48.2,48.7,48.5,48.4,48.2,48.4,  48.6,48.5,48.2.  calcukate g and the standard  error involved.
$${The}\:{eriodic}\:{time}\:{of}\:{a}\:{simple} \\ $$$${pendulum}\:{is}\:{given}\:{by}\:{T}=\mathrm{2}\pi\sqrt{\frac{{L}}{{g}}}. \\ $$$${if}\:{L}=\mathrm{100}\pm\mathrm{0}.\mathrm{1}{cm}\left({s}.{e}\right)\:{and}\:{the} \\ $$$${time}\:{s}\:{for}\:\mathrm{10}\:{ossilations}\:{are}: \\ $$$$\mathrm{48}.\mathrm{2},\mathrm{48}.\mathrm{2},\mathrm{48}.\mathrm{7},\mathrm{48}.\mathrm{5},\mathrm{48}.\mathrm{4},\mathrm{48}.\mathrm{2},\mathrm{48}.\mathrm{4}, \\ $$$$\mathrm{48}.\mathrm{6},\mathrm{48}.\mathrm{5},\mathrm{48}.\mathrm{2}. \\ $$$${calcukate}\:{g}\:{and}\:{the}\:{standard} \\ $$$${error}\:{involved}. \\ $$

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