Menu Close

The-first-and-second-ionization-potentials-of-helium-atoms-are-24-58-eV-and-54-4-eV-per-mole-respectively-Calculate-the-energy-in-kJ-required-to-produce-1-mole-of-He-2-ions-




Question Number 22368 by Tinkutara last updated on 16/Oct/17
The first and second ionization  potentials of helium atoms are 24.58 eV  and 54.4 eV per mole respectively.  Calculate the energy in kJ required to  produce 1 mole of He^(2+)  ions.
$$\mathrm{The}\:\mathrm{first}\:\mathrm{and}\:\mathrm{second}\:\mathrm{ionization} \\ $$$$\mathrm{potentials}\:\mathrm{of}\:\mathrm{helium}\:\mathrm{atoms}\:\mathrm{are}\:\mathrm{24}.\mathrm{58}\:\mathrm{eV} \\ $$$$\mathrm{and}\:\mathrm{54}.\mathrm{4}\:\mathrm{eV}\:\mathrm{per}\:\mathrm{mole}\:\mathrm{respectively}. \\ $$$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{energy}\:\mathrm{in}\:\mathrm{kJ}\:\mathrm{required}\:\mathrm{to} \\ $$$$\mathrm{produce}\:\mathrm{1}\:\mathrm{mole}\:\mathrm{of}\:\mathrm{He}^{\mathrm{2}+} \:\mathrm{ions}. \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *