Menu Close

the-first-n-even-numbers-are-known-if-one-number-is-deleted-then-the-average-of-remaining-numbers-is-2582-50-find-the-value-of-deleted-number-




Question Number 78979 by jagoll last updated on 22/Jan/20
the first n even  numbers are known. if one number  is deleted then the average  of remaining numbers is ((2582)/(50)).  find the value of deleted number.
thefirstnevennumbersareknown.ifonenumberisdeletedthentheaverageofremainingnumbersis258250.findthevalueofdeletednumber.
Commented by mr W last updated on 22/Jan/20
the 51 numbers are 2,4,6,...102  the deletete number is 70
the51numbersare2,4,6,102thedeletetenumberis70
Commented by jagoll last updated on 22/Jan/20
sir please explain me
sirpleaseexplainme
Commented by mr W last updated on 22/Jan/20
n even numbers: 2(1+2+...+n)=n(n+1)  deleted number: 2m with m≤n  ((n(n+1)−2m)/(n−1))=((2582)/(50))=((1291k)/(25k))  n(n+1)−((1291)/(25))(n−1)=2m≤2n  n^2 −((1316)/(25))n+((1291)/(25))≤0  ⇒1≤n≤51  ⇒1≤k≤2  k=1: ⇒n=26⇒no integer m  k=2: ⇒n=51⇒m=35 ⇒solution
nevennumbers:2(1+2++n)=n(n+1)deletednumber:2mwithmnn(n+1)2mn1=258250=1291k25kn(n+1)129125(n1)=2m2nn2131625n+12912501n511k2k=1:n=26nointegermk=2:n=51m=35solution
Commented by jagoll last updated on 22/Jan/20
thanks you lot sir
thanksyoulotsir

Leave a Reply

Your email address will not be published. Required fields are marked *