Question Number 37911 by Rio Mike last updated on 19/Jun/18
$$\mathrm{the}\:\mathrm{function}\:{f}\left({x}\right)\:\mathrm{is}\:\mathrm{defined}\:\mathrm{by} \\ $$$${f}\left({x}\right)\:=\begin{cases}{−{x}\:+\:\mathrm{1}\:,\:{for}\:{x}\leqslant\mathrm{3}}\\{{kx}\:−\:\mathrm{8}\:,\:{for}\:{x}\:\geqslant\:\mathrm{3}}\end{cases} \\ $$$${find}\:{the}\:{value}\:{of}\:{k}\:. \\ $$
Commented by math khazana by abdo last updated on 19/Jun/18
$${if}\:{k}\:{is}\:{continue}\:{we}\:{get}\:\mathrm{3}{k}−\mathrm{8}=−\mathrm{2}\:\Rightarrow\mathrm{3}{k}=\mathrm{6}\:\Rightarrow \\ $$$${k}=\mathrm{2}\:. \\ $$