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The-mean-and-standard-deviation-of-20-observation-are-found-to-be-10-and-2-respectively-On-rechecking-it-was-found-that-an-observation-8-was-incorrect-Calculate-the-incorrect-mean-and-standard-dev




Question Number 155574 by peter frank last updated on 02/Oct/21
The mean and standard deviation  of 20 observation  are found to be   10 and 2 respectively .On rechecking  it was found that  an observation  8 was incorrect.Calculate the incorrect  mean and standard deviation  (a)If the wrong iterm was  ommited  (b) If it is replaced by 12
Themeanandstandarddeviationof20observationarefoundtobe10and2respectively.Onrecheckingitwasfoundthatanobservation8wasincorrect.Calculatetheincorrectmeanandstandarddeviation(a)Ifthewrongitermwasommited(b)Ifitisreplacedby12
Answered by Rasheed.Sindhi last updated on 02/Oct/21
x^− =((x_1 +x_2 +...+8+...+x_(20) )/(20))=10   Sum=x_1 +x_2 +...+8+...+x_(20) =200  When 8 is ommited  Sum=200−8=192  Number of observation=20−1=19  x^− =((Σx_i )/n)=((192)/(19))=10(2/(19))  When 8 is replaced by 12:  Σx_i =200−8+12=204  x^− =((Σx_i )/n)=((204)/(20))=10(1/5)
x=x1+x2++8++x2020=10Sum=x1+x2++8++x20=200When8isommitedSum=2008=192Numberofobservation=201=19x=Σxin=19219=10219When8isreplacedby12:Σxi=2008+12=204x=Σxin=20420=1015
Commented by peter frank last updated on 02/Oct/21
great sir .thanks
greatsir.thanks

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