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The-number-of-five-digits-can-be-made-with-the-digits-1-2-3-each-of-which-can-be-used-atmost-thrice-in-a-number-is-




Question Number 171012 by mr W last updated on 06/Jun/22
The number of five digits can be made  with the digits 1, 2, 3 each of which can  be used atmost thrice in a number is
Thenumberoffivedigitscanbemadewiththedigits1,2,3eachofwhichcanbeusedatmostthriceinanumberis
Commented by otchereabdullai@gmail.com last updated on 07/Jun/22
nice question + nice solution!
nicequestion+nicesolution!
Answered by mr W last updated on 06/Jun/22
a=number of digits 1 in the number  b=number of digits 2 in the number  c=number of digits 3 in the number  0≤a,b,c≤3  a+b+c=5  coefficient of x^5  in 5!(1+(x/(1!))+(x^2 /(2!))+(x^3 /(3!)))^3   is 210. ⇒210 numbers
a=numberofdigits1inthenumberb=numberofdigits2inthenumberc=numberofdigits3inthenumber0a,b,c3a+b+c=5coefficientofx5in5!(1+x1!+x22!+x33!)3is210.210numbers
Commented by Tawa11 last updated on 06/Jun/22
Great sir
Greatsir

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