The-number-of-real-numbers-in-0-2pi-satisfying-sin-1-x-2sin-2-x-1-0-is- Tinku Tara June 4, 2023 None 0 Comments FacebookTweetPin Question Number 78885 by gopikrishnan last updated on 21/Jan/20 Thenumberofrealnumbersin[0,2pi]satisfyingsin−1x−2sin2x+1=0is Answered by mind is power last updated on 21/Jan/20 sin−(x)isdefindin[−1,1]sir Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Advanced-Calculus-Without-using-the-Feynman-s-trick-Find-the-value-of-I-0-1-Log-1-x-2-1-x-dx-m-n-Next Next post: make-n-the-subject-of-the-formular-if-A-p-1-r-100-n- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.
![The number of real numbers in [0,2pi] satisfying sin^(−1) x−2sin^2 x+1=0 is](https://www.tinkutara.com/question/Q78885.png)
![sin^− (x) is defind in[−1,1] sir](https://www.tinkutara.com/question/Q78893.png)