The-number-of-the-roots-of-the-quadratic-equation-8sec-2-6sec-1-0-is-

Question Number 20001 by Tinkutara last updated on 20/Aug/17

The number of the roots of the quadratic

equation {8 \sec}^{2} θ - 6 \sec θ + 1 = 0 is

Answered by mrW1 last updated on 20/Aug/17

{8 \sec}^{2} θ - 6 \sec θ + 1 = 0

(2 \sec θ - 1) (4 \sec θ - 1) = 0

\sec θ = \frac{1}{2} \Rightarrow \cos θ = 2 \dots (i)

or

\sec θ = \frac{1}{4} \Rightarrow \cos θ = 4 \dots (ii)

(i) and (ii) have no solution

\Rightarrow number of roots is 0 .

Commented by Tinkutara last updated on 20/Aug/17

Thank you very much Sir!