the-number-of-x-0-2pi-for-which-2sin-4-x-18cos-2-x-2cos-4-x-18sin-2-x-1-

Question Number 27706 by shivamgiri last updated on 13/Jan/18

t h e n u m b e r o f x ϵ [0, 2 π] f o r w h i c h ∣ \sqrt{} 2 {s i n}^{4} x + 18 {c o s}^{2} x - \sqrt{2 {c o s}^{4} x + 18 {s i n}^{2} x} ∣= 1