Question Number 31808 by Abadon last updated on 15/Mar/18
$$\mathrm{The}\:\mathrm{numeric}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{expression}\:\mathrm{is}: \\ $$$$ \\ $$$$\frac{\mathrm{Sec}\:\mathrm{1320}°}{\mathrm{2}}\:−\:\mathrm{2}\:\centerdot\:\mathrm{cos}\:\left(\frac{\mathrm{53}\pi}{\mathrm{3}}\right)\:+\:\left(\mathrm{tg}\:\mathrm{2220}°\right)^{\mathrm{2}} \\ $$
Commented by Tinkutara last updated on 15/Mar/18
1
Commented by MJS last updated on 15/Mar/18
$$\mathrm{1320}°=−\mathrm{120}° \\ $$$$\frac{\mathrm{53}\pi}{\mathrm{3}}=−\mathrm{60}° \\ $$$$\mathrm{2220}°=\mathrm{60}° \\ $$$$\mathrm{1}−\mathrm{1}+\mathrm{3}=\mathrm{3} \\ $$