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The-perimeter-of-a-square-and-a-rectangle-is-the-same-The-width-of-the-rectangle-is-6-cm-and-its-area-is-16-cm-2-less-than-the-area-of-the-square-Find-the-area-of-the-square-




Question Number 33805 by pieroo last updated on 25/Apr/18
The perimeter of a square and a rectangle is the  same. The width of the rectangle is 6 cm and its area  is 16 cm^2  less than the area of the square. Find the  area of the square.
$$\mathrm{The}\:\mathrm{perimeter}\:\mathrm{of}\:\mathrm{a}\:\mathrm{square}\:\mathrm{and}\:\mathrm{a}\:\mathrm{rectangle}\:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{same}.\:\mathrm{The}\:\mathrm{width}\:\mathrm{of}\:\mathrm{the}\:\mathrm{rectangle}\:\mathrm{is}\:\mathrm{6}\:\mathrm{cm}\:\mathrm{and}\:\mathrm{its}\:\mathrm{area} \\ $$$$\mathrm{is}\:\mathrm{16}\:\mathrm{cm}^{\mathrm{2}} \:\mathrm{less}\:\mathrm{than}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}.\:\mathrm{Find}\:\mathrm{the} \\ $$$$\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}. \\ $$
Answered by MJS last updated on 25/Apr/18
square=a×a  rectangle=6×b    6b+16=a^2   4a=2b+12 ⇒ b=2a−6    6(2a−6)+16=a^2   12a−20=a^2   a^2 −12a+20=0  (a−2)(a−10)=0  a_1 =2 ⇒ b_1 =2a_1 −6=−2 not valid  a_2 =10 ⇒ b_2 =2a_2 −6=14  area of the square=a_2 ^2 =100cm^2
$$\mathrm{square}={a}×{a} \\ $$$$\mathrm{rectangle}=\mathrm{6}×{b} \\ $$$$ \\ $$$$\mathrm{6}{b}+\mathrm{16}={a}^{\mathrm{2}} \\ $$$$\mathrm{4}{a}=\mathrm{2}{b}+\mathrm{12}\:\Rightarrow\:{b}=\mathrm{2}{a}−\mathrm{6} \\ $$$$ \\ $$$$\mathrm{6}\left(\mathrm{2}{a}−\mathrm{6}\right)+\mathrm{16}={a}^{\mathrm{2}} \\ $$$$\mathrm{12}{a}−\mathrm{20}={a}^{\mathrm{2}} \\ $$$${a}^{\mathrm{2}} −\mathrm{12}{a}+\mathrm{20}=\mathrm{0} \\ $$$$\left({a}−\mathrm{2}\right)\left({a}−\mathrm{10}\right)=\mathrm{0} \\ $$$${a}_{\mathrm{1}} =\mathrm{2}\:\Rightarrow\:{b}_{\mathrm{1}} =\mathrm{2}{a}_{\mathrm{1}} −\mathrm{6}=−\mathrm{2}\:\mathrm{not}\:\mathrm{valid} \\ $$$${a}_{\mathrm{2}} =\mathrm{10}\:\Rightarrow\:{b}_{\mathrm{2}} =\mathrm{2}{a}_{\mathrm{2}} −\mathrm{6}=\mathrm{14} \\ $$$$\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}={a}_{\mathrm{2}} ^{\mathrm{2}} =\mathrm{100}{cm}^{\mathrm{2}} \\ $$

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