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The-possible-value-of-x-that-satisfy-x-2-x-2-2x-x-2-2x-1-2017-x-R-and-x-2-2x-




Question Number 56719 by naka3546 last updated on 22/Mar/19
The  possible  value  of  x  that  satisfy  :          x^2  + ⌊x^2  − 2x⌋ + ⌈x^2  + 2x + 1⌉  =  2017  ,  x ∈  R^+   and   ⌊x^2 ⌋ − ⌈2x⌉  =  ...
Thepossiblevalueofxthatsatisfy:x2+x22x+x2+2x+1=2017,xR+andx22x=
Commented by tanmay.chaudhury50@gmail.com last updated on 22/Mar/19
Commented by tanmay.chaudhury50@gmail.com last updated on 22/Mar/19
Commented by tanmay.chaudhury50@gmail.com last updated on 22/Mar/19
Commented by tanmay.chaudhury50@gmail.com last updated on 22/Mar/19
x=25.923  ⌊(25.923)^2 ⌋−⌈2×25.923⌉  =⌊672.001929⌋−⌈51.846⌉  =672−52  =620
x=25.923(25.923)22×25.923=672.00192951.846=67252=620
Commented by naka3546 last updated on 22/Mar/19
Sir, the  answer  x  not  suitable  for  the  equation  above .  Please,  recheck  the  answer .
Sir,theanswerxnotsuitablefortheequationabove.Please,rechecktheanswer.
Commented by tanmay.chaudhury50@gmail.com last updated on 22/Mar/19
ok   let me check...
okletmecheck
Answered by mr W last updated on 23/Mar/19
x^2  + ⌊x^2  − 2x⌋ + ⌈x^2  + 2x + 1⌉  =  2017  x^2 +integer+integer=integer  ⇒x^2 =integer, say x^2 =n  n+n+⌊−2(√n)⌋+n+⌈2(√n)⌉+1=2017  since ⌊−x⌋=−⌈x⌉  ⇒⌊−2(√n)⌋+⌈2(√n)⌉=0  ⇒3n=2016  ⇒n=672  ⇒x=(√n)=(√(672))=4(√(42))≈25.923  ⌊x^2 ⌋−⌈2x⌉=672−52=620
x2+x22x+x2+2x+1=2017x2+integer+integer=integerx2=integer,sayx2=nn+n+2n+n+2n+1=2017sincex=x2n+2n=03n=2016n=672x=n=672=44225.923x22x=67252=620
Commented by naka3546 last updated on 23/Mar/19
but,  if  x  is  substituted  to  equation  above .  Is  x  right  ?    x^2  + ⌊x^2  − 2x⌋ + ⌈x^2  + 2x + 1⌉  =  2015    how  is  it  happen ?
but,ifxissubstitutedtoequationabove.Isxright?x2+x22x+x2+2x+1=2015howisithappen?
Commented by mr W last updated on 23/Mar/19
how did you get 2015? this is how it is:  x^2 =672  x=(√(672))≈25.92  2x≈51.8  ⌊x^2 −2x⌋=⌊672−51.8⌋=⌊620.2⌋=620  ⌈x^2 +2x+1⌉=⌈672+51.8+1⌉=⌈724.8⌉=725  x^2 +⌊x^2 −2x⌋+⌈x^2 +2x+1⌉=672+620+725=2017  so x=(√(672)) is correct.
howdidyouget2015?thisishowitis:x2=672x=67225.922x51.8x22x=67251.8=620.2=620x2+2x+1=672+51.8+1=724.8=725x2+x22x+x2+2x+1=672+620+725=2017sox=672iscorrect.

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