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The-reversible-expansion-of-an-ideal-gas-under-adiabatic-and-isothermal-conditions-is-shown-in-the-figure-Which-of-the-following-statement-s-is-are-correct-1-T-1-T-2-2-T-3-gt-T-1-3-




Question Number 24263 by Tinkutara last updated on 14/Nov/17
The reversible expansion of an ideal  gas under adiabatic and isothermal  conditions is shown in the figure. Which  of the following statement(s) is (are)  correct?  (1) T_1  = T_2   (2) T_3  > T_1   (3) w_(isothermal)  > w_(adiabatic)   (3) ΔU_(isothermal)  > ΔU_(adiabatic)
Thereversibleexpansionofanidealgasunderadiabaticandisothermalconditionsisshowninthefigure.Whichofthefollowingstatement(s)is(are)correct?(1)T1=T2(2)T3>T1(3)wisothermal>wadiabatic(3)ΔUisothermal>ΔUadiabatic
Commented by Tinkutara last updated on 14/Nov/17
Commented by ajfour last updated on 14/Nov/17
V_2  = ((nRT_2 )/P_2 ) = ((nRT_3 )/P_3 )  as P_2  > P_3    we can infer  T_2  > T_3  .  So    △U_(isothermal)  > △U_(adiabatic)    W_(isothermal (by gas))  > W_(adiabatic (by gas))   (Hence   Q_(isothermal)  > Q_(adiabatic)  ,  if we go use  Q_(to gas)  = W_(by gas) +△U_(of gas)  ).  so (1), (3), (4) .
V2=nRT2P2=nRT3P3asP2>P3wecaninferT2>T3.SoUisothermal>UadiabaticWisothermal(bygas)>Wadiabatic(bygas)(HenceQisothermal>Qadiabatic,ifwegouseQtogas=Wbygas+Uofgas).so(1),(3),(4).
Commented by Tinkutara last updated on 15/Nov/17
But please recheck (2) option, is it  true or not?
Butpleaserecheck(2)option,isittrueornot?
Commented by ajfour last updated on 15/Nov/17
T_1 = T_2     and  P_2  > P_3   Also      ((nR)/V_2 ) =(P_2 /T_2 ) = (P_3 /T_3 )     ⇒  T_3  = T_2 ((P_3 /P_2 )) < T_2   So     T_3  < T_1  .
T1=T2andP2>P3AlsonRV2=P2T2=P3T3T3=T2(P3P2)<T2SoT3<T1.
Commented by Tinkutara last updated on 15/Nov/17
Thank you very much Sir!
ThankyouverymuchSir!

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