The-rigid-body-of-mass-10kg-rotates-such-that-the-radius-of-the-circular-path-it-describes-is-5cm-It-it-moves-from-the-point-P-to-Q-in-5s-covering-an-angular-distance-of-30-Calculate-a-the-final-an

Question Number 31935 by NECx last updated on 17/Mar/18

T h e r i g i d b o d y o f m a s s 10 k g

r o t a t e s s u c h t h a t t h e r a d i u s o f t h e

c i r c u l a r p a t h i t d e s c r i b e s i s 5 c m . I t

i t m o v e s f r o m t h e p o i n t P t o Q i n

5 s c o v e r i n g a n a n g u l a r d i s t a n c e

o f 30 °, C a l c u l a t e :

a) t h e f i n a l a n g u l a r v e l o c i t y i f

t h e a n g u l a r a c c e l e r a t i o n i s 4 m / s^{2}

b) T h e m o m e n t o f i n e r t i a o f t h e

b o d y .

c) a n g u l a r m o m e n t u m

d) r o t a t i o n a l k i n e t i c e n e r g y