The-side-of-a-square-is-increasing-at-a-rate-of-0-1cms-1-Find-the-rate-of-increase-of-the-perimeter-of-the-square-when-the-length-of-side-is-4cm-

Question Number 37795 by Rio Mike last updated on 17/Jun/18

T h e s i d e o f a s q u a r e i s i n c r e a s i n g

a t a r a t e o f 0.1 {c m s}^{- 1} . F i n d t h e

r a t e o f i n c r e a s e o f t h e p e r i m e t e r

o f t h e s q u a r e w h e n t h e l e n g t h o f

s i d e i s 4 c m .

Answered by tanmay.chaudhury50@gmail.com last updated on 18/Jun/18

p = 4 a

\frac{d p}{d t} = 4 \frac{d a}{d t} p = p e r i m e t e r a = s i d e o f s q u a r e

\frac{d p}{d t} = 4 \times 0.1 = 0.4 c m / s e c